Quick Calculus Question

[Sin]

Is this correct?
Ln(e^x) = 1
and
e^ln(x) = 0

[ventsyv]

No. How can x^y be 0 if x!=0 to begin with ?

[Sin]

I'm sorry I made a typo and the question was incorrect to begin with.

[Sin]

What I meant to ask (If I was not so high when I posted the question the first time) is that if this is correct:

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The derivative of e^(lnx + pi) = e^ pi

Does the Lnx cancel out?

[t i l e x]

No.

(e^(ln x + pi)) ' = (e^(ln x + pi))(1/x) = (e^(ln x + pi))/x

[Jimbo]

e^(ln(x) + pi) = (e^(ln(x)))(e^pi) = x*e^pi => d/dx (e^(ln(x) + pi)) = e^pi

[Sin]

e^(ln(x) + pi) = (e^(ln(x)))(e^pi) = x*e^pi => d/dx (e^(ln(x) + pi)) = e^pi

Twas what I thought.
Thanks both of you.