3d vectors

[joyrider]

I have read a little about 3d vectors & i was wondering whether anyone can verify that this is correct:

I have 3 points on a graph - (0,0,0), (0,0,4), (4,0,0). Would it be true to state that the straight line going from (0,0,4) to (4,0,0) equals 32^.5?

This is how I did it: first I found the distances between (0,0,0) & (4,0,0) on the x-axis = 4 units, & between (0,0,0) & (0,0,4) on the z axis = 4 units. After that, I used Pythagoras's theorem to find the straight line from (0,0,4) to (4,0,0), which involves the z & x axis.

Here is the calculation for that:

Code: Select all

a^2 + b^2 = c^2 /* a = dist (0,0,0)to(4,0,0); b = dist (0,0,0)to(0,0,4); c = dist (0,0,4)to(4,0,0)*/

4^2 + 4^2 = c^2
c = 32^.5


[Blueteeth]

I don't see anything wrong , it's totally right .

[Kybo Ren]

I believe the distance formula for 3 dimensions is as follows:

That leaves us with
" sqrt( (4)^2 + (0)^2 + (-4)^2 )"

Which simplifies to

" sqrt( 32 ) "

So I belive that you are correct.

[leas5040]

I believe the distance formula for 3 dimensions is as follows:

You would be correct. The distance formula carries into the 3rd dimension. Way to think this one through though joyrider